We Are Discuss About CODECHEF SOLUTION
Mean and Median Codechef Solution
Mean and Median Codechef Solution
Problem
Chef has two numbers X and Y. Chef wants to find three integers A, B, and C such that:
- -1000 \le A, B, C \le 1000
- mean([A, B, C]) = X
- median([A, B, C]) = Y
Can you help Chef find such three integers?
As a reminder, mean([P, Q, R]) = \frac{P + Q + R}{3} and median([P, Q, R]) is the element at the 2^{nd} (middle) position after we sort [P, Q, R] in non-decreasing order.
Input Format
- The first line contains a single integer T — the number of test cases. Then the test cases follow.
- The first and only line of each test case contains two space-separated integers X and Y — the required mean and median of the three integers.
Output Format
For each test case, output three integers A, B, C which satisfy the given conditions.
It is guaranteed that an answer always exists under the given constraints.
If multiple answers exist, output any.
Constraints
- 1 \leq T \leq 10^5
- -100 \le X, Y \le 100
Sample 1:
3 5 5 67 100 4 5
5 5 5 0 100 101 0 5 7
Explanation:
Test Case 1: mean([5, 5, 5]) = \frac{5 + 5 + 5}{3} = 5, median([5, 5, 5]) = 5.
Test Case 2: mean([0, 100, 101]) = \frac{0 + 100 + 101}{3} = \frac{201}{3} = 67, median([0, 100, 101]) = 100.
Test Case 3: mean([0, 5, 7]) = \frac{0 + 5 + 7}{3} = 4, median([0, 5, 7]) = 5.
SOLUTION
Mean and Median Codechef Solution
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