Mean and Median Codechef Solution

Problem

Chef has two numbers $X$ and $Y$. Chef wants to find three integers $A,B,$ and $C$ such that:

• $-1000\le A,B,C\le 1000$
• $mean([A,B,C])=X$
• $median([A,B,C])=Y$

Can you help Chef find such three integers?

As a reminder, mean([P, Q, R]) = \frac{P + Q + R}{3}mean([P,Q,R])=3P+Q+R​ and $median([P,Q,R])$ is the element at the 2^{nd}2nd (middle) position after we sort $[P,Q,R]$ in non-decreasing order.

Input Format

• The first line contains a single integer $T$ — the number of test cases. Then the test cases follow.
• The first and only line of each test case contains two space-separated integers $X$ and $Y$ — the required mean and median of the three integers.

Output Format

For each test case, output three integers $A,B,C$ which satisfy the given conditions.

It is guaranteed that an answer always exists under the given constraints.

If multiple answers exist, output any.

Constraints

Sample 1:

3
5 5
67 100
4 5

5 5 5
0 100 101
0 5 7

Explanation:

Test Case 1: mean([5, 5, 5]) = \frac{5 + 5 + 5}{3} = 5mean([5,5,5])=35+5+5​=5, $median([5,5,5])=5$.

Test Case 2: mean([0, 100, 101]) = \frac{0 + 100 + 101}{3} = \frac{201}{3} = 67mean([0,100,101])=30+100+101​=3201​=67, $median([0,100,101])=100$.

Test Case 3: mean([0, 5, 7]) = \frac{0 + 5 + 7}{3} = 4mean([0,5,7])=30+5+7​=4, $median([0,5,7])=5$.